ζ4ζ
£5km
-mθ-
=ζΤά
=V,€=ΐ²
Βl
ζΤ1Κ
‘φ EκY
(²κ}X^[Y)
16'51"
ζΤ2Κ
Δμ υΖ
(`m)
20'05"
ζΤ3Κ
k bO
(εͺλ€ο)
21'58"
ͺ
²έΓή―Έ½Φ